MATH SOLVE

4 months ago

Q:
# Solve 5 over x minus 5 equals the quantity of x over x minus 5, minus five fourths for x and determine if the solution is extraneous or not

Accepted Solution

A:

5/(x-5)=x/(x-5)-5/4.

Multiply through by 4(x-5):

20=4x-5(x-5).

20=4x-5x+25=25-x, x=5.

This is an extraneous solution because when x=5, the denominators become zero so division by zero occurs, and the result is meaningless.

Multiply through by 4(x-5):

20=4x-5(x-5).

20=4x-5x+25=25-x, x=5.

This is an extraneous solution because when x=5, the denominators become zero so division by zero occurs, and the result is meaningless.