What is the range, min, and max of the function f(x)=13-20x-x²-3x⁴Please Explain how you found these

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Answer:range: (-∞, 29.4336]min: -∞max: 29.4336Step-by-step explanation:I found these using a graphing calculator. (See attached)The function is a polynomial of 4th degree with a negative leading coefficient. (The coefficient of the 4th-degree term is -3.) Therefore, it opens downward and has a range that extends to -∞. This function only has one global maximum and no local minimum._____The maximum can be found by solving the cubic equation that results from taking the derivative of this function and finding the root of that:   df/dx = -12x^3 -2x -20 = 0There are formulas for the solutions of a cubic, but the one negative real root of this cubic can be found easily with a graphing calculator using iteration:   x ≈ -1.13879908894.Dividing by -2, the above derivative function can be written as ...   g(x) = 6x^3 +x +10The one real zero of it can be found using Newton's Method iteration. The Newton's Method iterator function is   h(x) = x - g(x)/g'(x)where g'(x) is the derivative of g(x), often available as a function on the graphing calculator. The starting value for the iteration can be the x-value obtained from the graph: -1.139. It only takes about 2 or 3 iterations to find x to the precision of the calculator: x = h(h(x)). This x is the x-coordinate of the maximum, so f(x) is the maximum value: 29.4335546516.__The attachments show the function definitions and their use for finding the maximum of f(x) using a TI-84 calculator. Y₁ is the function f(x); Y₂ is its derivative, shown above as g(x). Y₃ is the iterating function, shown above as h(x). The nDeriv( ) function is a calculator function that finds the numerical derivative of its argument.