£65 of candy was divided into 4 different boxes the 2nd Box contained twice the amount of the 1st Box the 3rd Box contained a to more pounds than the 1st Box the last Box contain 1/4 the amount in the 2nd Box how much candy was in each Box

Answer:The fourth box contains 7 candiesSolution: Let us assume that the first box contains x amount The second box contain twice of first box that is = 2x The third box contains two pound more than the first box that is = (x+2) The last box contains [tex]\frac{1}{4}[/tex] the amount in the 2nd Box is [tex]\left(\frac{1}{4} \times 2 x\right)=\left(\frac{x}{2}\right)[/tex]Now the total candy in the box = 65 So we can say, [tex]x+2 x+(x+2)+\left(\frac{x}{2}\right)=65[/tex][tex]\Rightarrow 4 x+\left(\frac{x}{2}\right)=65-2[/tex][tex]\Rightarrow 4 x+\left(\frac{x}{2}\right)=63[/tex][tex]\Rightarrow 8 x+x=63 \times 2[/tex][tex]\Rightarrow 9 x=63 \times 2[/tex] [tex]\Rightarrow \quad x=\frac{63 \times 2}{9}=14[/tex]So, first box contains 14 candy Second box contains [tex](2\times14) =28 candy[/tex] The third box contain [tex](14+2) =16 candy[/tex]The fourth box contains [tex]\left(\frac{14}{2}\right)=7[/tex]